resistors in series experiment class 10

• Skip to main content
• Skip to secondary menu
• Skip to primary sidebar
• Skip to footer

A Plus Topper

Improve your Grades

CBSE Class 10 Science Lab Manual – Resistors in Series

December 1, 2022 by Veerendra

Aim To determine the equivalent resistance of two resistors, when connected in series combination.

Materials Required Two standard resistance coils (or resistors), ammeter (0-1.5A), voltmeter (0-1.5V), one-way key, low resistance rheostat, connecting wires, a piece of sand paper and ceil or battery eliminator.

• Note the least count and the zero error (if any) of the given ammeter and voltmeter.
• Clean the ends of connecting wires using a sand paper.

• Connect the resistances in series as shown in block diagram or circuit diagram given in Fig. 2.
• Put the plug in the key and take the readings of ammeter and voltmeter (as done in Experiment 5).
• Repeat the step 5 three times by changing the position of the sliding contact of the rheostat (as done in Experiment 5).
• Tabulate the readings and find the ratio of V and I. It will give the equivalent resistance of the combination.

Observation

• Least count of ammeter = …………. A
• Zero error of ammeter = ………… A
• Least count of voltmeter = ………… V
• Zero error of voltmeter = …………. V
• Zero correction in ammeter reading = ………. A

Calculations

• Mean value of R 1 = ………. Ω
• Mean value of R 2 = ……….. Ω
• By calculation, R’ s = R 1 + R 2 = ………… Ω
• By experiment, R s = ………… Ω Difference in both values, R s -R’ s = ……… Ω
• There is a close agreement between the calculated value and the value obtained by the experiment. Hence, R s = R 1 + R 2 is verified.
• Equivalent resistance, R s  = …………. Ω

Percentage Error It can be found by using the following relation: Percentage Error = \(\frac { Experimental\quad value-Calculated\quad Value }{ Calculated\quad Value } \times 100\) = \(\frac { { R }_{ s }-{ R’ }_{ s } }{ { R’ }_{ s } } \times 100\) = …….. % It shows that the percentage error is within the experimental error.

Precautions

• Remove the dust and other insulating particles from the ends of connecting wire, by rubbing it with sand paper.
• All the connections should be tight and properly done as per the circuit diagram.
• Take out the plug from the plug key in between the two observations.
• A low resistance rheostat should be used in the circuit to obtain a large variation in the current.
• The thick copper connecting wires should be used in the circuit.
• The positive terminal of the ammeter and voltmeter must be connected to the positive terminal of the battery or battery eliminator.
• Never connect the two terminals of the cell without any resistance.
• The pointers of the ammeter and voltmeter should be at zero mark when no current flows through them.
• Current should be passed through the circuit for a short time while taking observations; otherwise current would cause unnecessary heating in the circuit. Heating may change the resistance of resistors.
• The ammeter should be connected in series with the combination of resistors such that the current enters at the positive terminal and leaves at the negative terminal of the ammeter.
• Voltmeter should always be connected in parallel to the combination of resistors.

Sources of Error

• Reading error may be possible while observing the pointer of ammeter and voltmeter.
• Thick connecting wires may not be available at the time of performing the experiment.
• Area of cross-section of resistance may not be uniform across the length of the wire.
• The high resistance rheostat may be used.
• Current may be allowed for the longer period through the circuit.
• The terminal screws of the given instruments may not be tighten properly.

Viva – Voce

Question 1. If two resistors having resistances of 2 Ω and 4 Ω, respectively are connected in a series combination in an electric circuit, what will be the net resistance in the Circuit? [NCERT] Answer: According to series combination, R net =R 1 +R 2 ⇒ R net = (2 + 4) Ω          {∵R 1 = 2 Ω, R 2 = 4Ω} ⇒ R net = 6 Ω

Question 2. In an electric circuit, a resistor of 5 Ω resistance is connected to a battery (5V), through an ammeter and a plug key. Now in this circuit, an another resistor of 10 Ω is connected in series with the 5 Ω resistor. Will there be any change in the ammeter reading? How much? [NCERT] Answer: Since, resistors are added in series, therefore there will be a change in the current. I 1 = \(\frac { V }{ R } =\frac { 5 }{ 5 }\) =1A and I 2 = \(\frac { V }{ { R }_{ 1 }+{ R }_{ 2 } } =\frac { 5 }{ 10+5 } =\frac { 1 }{ 3 } A\) Therefore, change in ammeter reading will be from 1 A to 0.33 A.

Question 3. In the above question, what is the potential difference across two ends of the resistor of 5 Ω resistance, when it is alone in the circuit? What is the potential difference across the two ends of resistor of 5 Ω resistance, when it is connected in series with the resistor of 10 Ω resistance? What is the potential difference across the series combination? [NCERT] Answer: Consider V 1 be the potential difference across two ends of the resistor of 5 Ω resistance, when it is connected alone. => V 1 = I 1 R = \(\frac { 1 }{ 3 }\) x 5 = \(\frac { 5 }{ 3 }\) V Consider V 2 be the potential difference across two ends of resistor of 5 Ω resistance, when it is connected to 10 Ω resistor in series. => V 2 = I 2 R = \(\frac { 1 }{ 3 }\) x 5 = \(\frac { 5 }{ 3 }\) V Potential difference across the series combination is V 3 = I 2 R s = \(\frac { 1 }{ 3 }\) x (5 +10) = \(\frac { 1 }{ 3 }\) x 15 = 5V The potential difference across series combination is equal to applied potential difference.

Question 4. How will you find the equivalent resistance, when they are connected in series? Answer: The equivalent resistance of two resistors R 1 and R 2 , is determined by R s = R 1 + R 2

Question 5. What is the relationship between V and R for the series combination? Answer: Voltage applied across combination of resistances is directly proportional to the resistance of series combination.

Question 6. What happens to the resistance of the resistor, if the current through it increases? Answer: It remains unchanged because the resistance does not depend on the current flowing through it.

Question 7. When two unequal resistances are connected in series, what will be the potential difference across each resistor? Answer: When two unequal resistances are connected in series, the potential difference across each resistor will be different.

Question 8. What happens to the ammeter reading if two resistors of the same value are connected in series in the circuit? Answer: The deflection in ammeter is reduced to half of the previous value, i.e. ammeter shows half of the previous reading.

Question 9. Why resistance becomes more in series combination? Answer: The effective length of all the resistors in series combination increases. Hence, equivalent resistance of the combination increases as R ∝ I

Question 10. When do we put the resistances in series combination? Answer: A, When we have the smaller value of resistance and need the greater value of resistance, we put them in series combination.

Question 11. In a circuit, if two resistors of resistances 5Ω and 10Ω are connected in series. Compare the current passing through the two resistors. Answer: In a series combination, same current passes through all the resistors. Thus, the ratio of current will be 1:1.

Question 12. Why current should be passed for a short time through the circuit while taking observations? Answer: Current passed through the circuit for longer time while taking observations, can cause unnecessary heating in the circuit, which may change the resistance of resistors.

Question 13. Mention the use of rheostat in the circuit. Answer: To change the current in the circuit which can be done by changing the sliding contact of the rheostat.

Question 14. Can you mention one disadvantage of series connection? Answer: In series connection, if any one component fails to work, the circuit breaks and none of the components works.

Science Lab Manual Science Practical Skills Science Labs Math Labs Math Labs with Activity

• Picture Dictionary
• English Speech
• English Slogans
• English Letter Writing
• English Essay Writing
• English Textbook Answers
• Types of Certificates
• ICSE Solutions
• Selina ICSE Solutions
• ML Aggarwal Solutions
• HSSLive Plus One
• HSSLive Plus Two
• Kerala SSLC
• Distance Education

CBSE Class 10 Science Practicals Determination of the equivalent resistance of two resistors when connected in series and parallel

CBSE Class 10 Practicals Science Determination of the equivalent resistance of two resistors when connected in series and parallel

To determine the equivalent resistance of two resistors when connected in series and parallel

Objective of the experiment…., instruments required for the experiment…...

Resistor coils (100 Ω, 200 Ω, 300 Ω), voltmeter (range 0 – 10 V), battery eliminator, ammeter (range 0 – 250 mA), plug key, connecting wires, rheostat etc.

Assumptions used for the experiment…..

1.) resistors in series:.

2) pd of circuit,V = V 1 + V 2 + V 3

2.) Resistors in parallel:

Important equations:.

iii.) Equivalent resistance , 1/R P = 1/R 1 + 1/R 2 + 1/R 3

Circuit diagram showing the experimental condition……

Procedure to verify the law of resistance and find the equivalent resistance…., resistors in series., resistors in parallel., observation table….

Calculations……!

For series combination

2) R 2 = V 2 /I 2

3) R 3 = V 3 /I 3

Results from the experiment…

Conclusions from the experiment…, precautions that should be followed while performing experiment…., some important questions that needs to revised for the experiment….

pd of circuit, V = V 1 + V 2 + V 3

1.) To decrease effective resistance of circuit so as to increase the value of current flow, resistors are connected in parallel.

Leave a Reply Cancel reply

We have a strong team of experienced teachers who are here to solve all your exam preparation doubts, up scert solutions class 7 english chapter 2 – the holy ganga, up scert solutions class 7 english chapter 1 – thank you god, chhattisgarh class 4 math measurement solution, telangana scert class 5 evs chapter 5 our body parts – sense organs solution.

• 10 Science Lab Manual
• Combination Of Resistances Solution

Combination Of Resistances

Class 10 th science lab manual cbse solution.

• AIMTo determine of the equivalent resistance of two resistors when connected in series.…
• AIMTo determine the equivalent resistance of two resistors when connected in parallel.…

What is zero error?

What is least count?

• Suppose the ammeter you are using in this experiment does not have positive and negative…
• Suppose the deflection go beyond the full scale. What will you infer from such…
• Why it is advised to clean the ends of connecting wires before connecting them?…
• While taking the reading the student observe that pointer on voltmeter is 15th division…

In a series combination, what happens to voltage and current?

• What is the equivalent resistance for a series combination parallel combination?…
• In parallel combination, is the current same or voltage same in the circuit?…

Why are the standard resistances made up of manganin wire?

What should be characteristics of standard resistance?

Why connecting wires are made of copper?

• How many times will be the equivalent resistance of two identical resistors be increased…

Can you distinguish between resistor and resistance?

In what way household appliances should be connected?

• Draw a diagram which shows the direction of current the current carriers.…

Why is ammeter always connected in series in a circuit?

Why is voltmeter always connected in parallel?

Which device has high resistance voltmeter or ammeter?

Why closed path is required for flow of current?

• What happens to the resistance of a conductor if the area of cross section is increased?…
• Why are copper and aluminium wires used for electrical transmission?…
• What helps to maintain the potential difference across a conductor?…
• Write one advantage of connecting devices in parallel and not in series.…
• Give one difference between open circuit closed circuit?

Lab Experiment 5a

AIM To determine of the equivalent resistance of two resistors when connected in series.

MATERIALS REQUIRED

Two standard resistance coils, ammeter, voltmeter, one - way plug key, low resistance rheostat, connecting wires, cell or battery eliminator.

When two or more resistors are connected end to end, then they provide only one path to the flow of current i.e., the same current flow through each resistor. Then, they are in series combination.

V = V 1 + V 2

let v be the applied potential difference by a dc source across the combination of unknown resistors R 1 and R 2 .

According to ohms law, for each resistor,

V 1 = IR 1 , V 2 = IR 2

Then the equivalent resistance of the series combination of two resistors is given by

R s = R 1 + R 2

Circuit Diagram

Apparatus Arrangement:

1. Join the circuit as shown in the circuit diagram or apparatus arrangement with one of the unknown resistors.

2. Find the values of two given unknown resistors R 1 and R 2 one by one.

3. Tabulate at least three readings of ammeter and voltmeter for the given unknown resistor.

4. By using Ohm’s law, find the value of each resistance.

5. Connect the given resistors in series combination between the terminals of voltmeter as shown in the figure above

6. Plug in the one - way plug key and note the readings of ammeter and voltmeter in the observation table.

7. Repeat the step 6 three times by changing the position of the sliding contact of the rheostat

8. Write the readings and find the ratio of V and I. It will give the equivalent resistance of the combination.

OBSERVATION TABLE

OBSERVATIONS

1. Least count of ammeter:

The range of the ammeter =500 - 0 mA = 500 mA = 0.5 A

The number of divisions in between two consecutive values= 10

2. Zero error of ammeter:

The needle of the ammeter points towards zero of the main scale of the ammeter, therefore no zero error .

3. Least count of voltmeter:

The range of voltmeter = 2 - 0 V= 2 V.

The number of division in small scale between two division on the main scale

4. Zero error of voltmeter = 0 V.

CALCULATIONS

1. Mean value of R 1 = 2.06 Ω

2. Mean value of R 2 = 4.06 Ω

Equivalent value of series combination:

(a) by calculation, = 2 Ω + 4 Ω = 6 Ω

(b) by experiment, = 5.99 Ω

Difference in both value = R exp – R calculated = 0.01 Ω

1. The calculated and the experimental value of equivalent resistance are similar. Hence R s = R 1 + R 2 is verified.

2. The equivalent resistance, R s = 5.99 Ω

PERCENTAGE ERROR

PRECAUTIONS

1. Remove the oxide layer from the ends of connecting wires by rubbing it with sandpaper.

2. All connections should be kept tight and properly done as per the circuit diagram.

3. Take out the plug from the plug key in between the two observations to avoid heating.

4. A low resistance rheostat should be used in the circuit to obtain a large variation in current.

5 A thick copper connecting wire should be used in the circuit.

Lab Experiment 5b

AIM To determine the equivalent resistance of two resistors when connected in parallel.

Two standard resistance coils, ammeter, voltmeter, one-way plug key, a low resistance rheostat, connecting wires, battery or battery eliminator.

An arrangement in which resistors are connected between two common ends of the circuit in such a way that the potential difference across each resistance is equal to the applied voltage, then such an arrangement is called the parallel combination

As shown in the figure, two resistances R 1 and R 2 are connected between two points A and B in the parallel combination.

Let the potential applied by the dc source to this combination be V. let I 1 and I 2 be the current measured by ammeters, connected in series with the resistor R 1 and R 2 respectively, then

I = I 1 +I 2

According to ohms law, I 1 = V/R 1 and I 2 = V/R 2

If R p , is the equivalent resistance of the given parallel combination having the same potential difference a the applied potential, then

Apparatus Arrangement Diagram:

Connect all the resistors in parallel combination between the two terminals of the voltmeter as shown in the figure given below.

1. Connect the circuit as shown in the circuit diagram with one of the unknown resistors.

2. By using Ohm’s law, find the value of each resistance, Let it be R 1 or R 2 .

3. Connect the given resistors in parallel combination between the two terminals of the voltmeter as shown in the circuit diagram above.

4. Plug in the key and take the readings of ammeter and voltmeter.

5. Repeat the step 5 for three times by changing the position of the sliding contact of the rheostat.

6. Record the readings in the observation table and find the ratio of V and I. It will give the equivalent resistance of the combination.

The image of the ammeter is attached here:

The range of the ammeter = 500 - 0 mA = 500 mA = 0.5 A

The number of divisions in between two consecutive values = 10

The needle of the ammeter points towards zero of the main scale of the ammeter.

The range of voltmeter = 2 - 0 V = 2 V.

1. Mean value of R 1 = 2.083 Ω

2. Mean value of R 2 = 1.973 Ω

Equivalent value of parallel combination:

(a) by calculation, R = 1 Ω

(b) by experiment, R = 1.08 Ω

1. The equivalent resistance of parallel combination = 1.08 Ω.

2. There is a direct agreement between the calculated value and the experimental value.

Percentage error = 8%

Precautions:

1. All the connection should be tight and properly done as per circuit diagram.

2. Take out the plug from the plug key in between the two observations.

3. A low resistance rheostat should be used in the circuit to obtain large variation in current.

4. A thick copper connecting wires should be used in the circuit.

5. The positive terminal of the ammeter and voltmeter must be connected with the positive terminal of the battery or battery eliminator.

Viva Questions

If the pointer of the meter does not coincide with zero of the scale, this type of error in reading of the scale is called a Zero error.

The smallest value that can be measured accurately by an instrument is called its least count.

Suppose the ammeter you are using in this experiment does not have positive and negative markings , How will you use such ammeter?

We will connect the ammeter or Voltmeter arbitrary in the circuit and observe the deflection of the pointer. If the deflection occurs in the opposite direction then by interchanging the terminal connection, we can use these devices.

Suppose the deflection go beyond the full scale. What will you infer from such observation?

If the deflection on ammeter goes beyond the full scale , we infer that:

1. The higher range ammeter has to be used to measure higher current.

2. The applied voltage is very high thus will require a high range voltmeter to measure applied voltage

Why it is advised to clean the ends of connecting wires before connecting them?

It is advised to clean the ends of connecting wires to remove the insulating layer if any from to ends of the wire. Also, to remove any dust from the ends of the wire to ensure better flow of electrons in the junction.

While taking the reading the student observe that pointer on voltmeter is 15th division when voltmeter least count is 0.05V. Find the observed reading of voltmeter?

Observed reading = Least count × Number of division

= 0.05 × 15

In series combination:

1. Current flowing across a different resistor connected in series are same

2. Voltage in a series is the sum of the voltage across the different resistor.

What is the equivalent resistance for a series combination & parallel combination?

The equivalent resistance R eq =R 1 +R 2 +…….+R n .

The equivalent resistance in a parallel connection is given as:

In parallel combination, is the current same or voltage same in the circuit?

In parallel combination:

1. The voltage across the resistor remains the same.

2. The current across the combination is the sum of the current across the different resistor.

The standard resistance coils are made up of manganin wire. The reasons are:

i. The variation of resistance with a rise in temperature is very less as compared to other metal.

ii. The resistivity of the material is very high & any resistance value can be made from it. Therefore, it is used as standard resistance.

1. The value of resistance should not change with time.

2. The value of resistance should almost remain the same with a change in temperature.

3. It should be convenient sizes.

The connecting wires are made of copper because copper has low resistivity and it conducts the current without offering much resistance.

How many times will be the equivalent resistance of two identical resistors be increased if the parallel arrangement is changed to a series arrangement?

That of series combination is R s = 2R. Thus, we get R s = 4R p, i.e., equivalent resistance increases four times.

The resistor is a device which offers resistance, whereas resistance is the property of the resistor.

The household appliances should be connected in parallel in order to get equal voltage for each appliance and ensure that if one is a switch “on” or ”off,” others working are not affected.

Draw a diagram which shows the direction of current & the current carriers.

The direction of current is from the positive terminal of the battery, it goes on through the components & then enters through negative terminal.

The current carriers are electrons and the motion of electrons is opposite from the electric current.

Ammeter is always connected in series with circuit as it should offer low resistance to the components added in the series. In this ways, the current can be measured accurately in low resistance.

Voltmeter should be connected in parallel because in parallel connection, the potential difference is same.

Voltmeter has very high resistance and ammeter has negligible resistance. This is because when voltmeter is connected in parallel across any two points, it will draw very less current (due to high resistance), hence it can measure the voltage accurately.

The closed path is necessary for electrons to move in a particular direction.

What happens to the resistance of a conductor if the area of cross section is increased?

The resistance will decrease because the resistance has an in-direct relationship with the area.

Where, ρ is the constant (resistivity of the material)

Why are copper and aluminium wires used for electrical transmission?

Both copper and aluminium are good conductors of electricity, hence they are employed for electrical transmission.

What helps to maintain the potential difference across a conductor?

The cell (battery eliminator) maintains the potential difference across a conductor.

Write one advantage of connecting devices in parallel and not in series.

In parallel connection, if one device fails to work, others will continue working as the potential difference across parallel connection is same.

Give one difference between open circuit & closed circuit?

In open circuit, no current can flow across the circuit. Whereas, in closed circuit, continuous current flows.

• Andhra Pradesh
• Chhattisgarh
• West Bengal
• Madhya Pradesh
• Maharashtra
• Jammu & Kashmir
• NCERT Books 2022-23
• NCERT Solutions
• NCERT Notes
• NCERT Exemplar Books
• NCERT Exemplar Solution
• States UT Book
• School Kits & Lab Manual
• NCERT Books 2021-22
• NCERT Books 2020-21
• NCERT Book 2019-2020
• NCERT Book 2015-2016
• RD Sharma Solution
• TS Grewal Solution
• TR Jain Solution
• Selina Solution
• Frank Solution
• Lakhmir Singh and Manjit Kaur Solution
• I.E.Irodov solutions
• ICSE - Goyal Brothers Park
• ICSE - Dorothy M. Noronhe
• Micheal Vaz Solution
• S.S. Krotov Solution
• Evergreen Science
• KC Sinha Solution
• ICSE - ISC Jayanti Sengupta, Oxford
• ICSE Focus on History
• ICSE GeoGraphy Voyage
• ICSE Hindi Solution
• ICSE Treasure Trove Solution
• Thomas & Finney Solution
• SL Loney Solution
• SB Mathur Solution
• P Bahadur Solution
• Narendra Awasthi Solution
• MS Chauhan Solution
• LA Sena Solution
• Integral Calculus Amit Agarwal Solution
• IA Maron Solution
• Hall & Knight Solution
• Errorless Solution
• Pradeep's KL Gogia Solution
• OP Tandon Solutions
• Sample Papers
• Previous Year Question Paper
• Important Question
• Value Based Questions
• CBSE Syllabus
• CBSE MCQs PDF
• Assertion & Reason
• New Revision Notes
• Revision Notes
• Question Bank
• Marks Wise Question
• Toppers Answer Sheets
• Exam Paper Aalysis
• Concept Map
• CBSE Text Book
• Additional Practice Questions
• Vocational Book
• CBSE - Concept
• KVS NCERT CBSE Worksheets
• Formula Class Wise
• Formula Chapter Wise
• Toppers Notes
• Most Repeated Question
• Diagram Based Question
• Study Planner
• JEE Previous Year Paper
• JEE Mock Test
• JEE Crash Course
• JEE Sample Papers
• Important Info
• SRM-JEEE Previous Year Paper
• SRM-JEEE Mock Test
• VITEEE Previous Year Paper
• VITEEE Mock Test
• BITSAT Previous Year Paper
• BITSAT Mock Test
• Manipal Previous Year Paper
• Manipal Engineering Mock Test
• AP EAMCET Previous Year Paper
• AP EAMCET Mock Test
• COMEDK Previous Year Paper
• COMEDK Mock Test
• GUJCET Previous Year Paper
• GUJCET Mock Test
• KCET Previous Year Paper
• KCET Mock Test
• KEAM Previous Year Paper
• KEAM Mock Test
• MHT CET Previous Year Paper
• MHT CET Mock Test
• TS EAMCET Previous Year Paper
• TS EAMCET Mock Test
• WBJEE Previous Year Paper
• WBJEE Mock Test
• AMU Previous Year Paper
• AMU Mock Test
• CUSAT Previous Year Paper
• CUSAT Mock Test
• AEEE Previous Year Paper
• AEEE Mock Test
• UPSEE Previous Year Paper
• UPSEE Mock Test
• CGPET Previous Year Paper
• BCECE Previous Year Paper
• JCECE Previous Year Paper
• Crash Course
• Previous Year Paper
• NCERT Based Short Notes
• NCERT Based Tests
• NEET Sample Paper
• Previous Year Papers
• Quantitative Aptitude
• Numerical Aptitude Data Interpretation
• General Knowledge
• Mathematics
• Agriculture
• Accountancy
• Business Studies
• Political science
• Enviromental Studies
• Mass Media Communication
• Teaching Aptitude
• Verbal Ability & Reading Comprehension
• Logical Reasoning & Data Interpretation
• CAT Mock Test
• CAT Important Question
• CAT Vocabulary
• CAT English Grammar
• MBA General Knowledge
• CAT Mind Map
• CAT Study Planner
• CMAT Mock Test
• SRCC GBO Mock Test
• SRCC GBO PYQs
• XAT Mock Test
• SNAP Mock Test
• IIFT Mock Test
• MAT Mock Test
• CUET PG Mock Test
• CUET PG PYQs
• MAH CET Mock Test
• MAH CET PYQs
• NAVODAYA VIDYALAYA
• SAINIK SCHOOL (AISSEE)
• Mechanical Engineering
• Electrical Engineering
• Electronics & Communication Engineering
• Civil Engineering
• Computer Science Engineering
• CBSE Board News
• Scholarship Olympiad
• School Admissions
• Entrance Exams
• All Board Updates
• Miscellaneous
• State Wise Books
• Engineering Exam

CBSE Class 10 Lab Manual for Chapter 2 Resistors In Series PDF Download

CBSE Class 10 Lab Manual Chapter 2 Resistors In Series Download here in pdf format. These Lab Manual may be freely downloadable and used as a reference book. Learning does not mean only gaining knowledge about facts and principles rather it is a path which is informed by scientific truths, verified experimentally. Keeping these facts in mind, CBSE Class 10 Lab Manual for Chapter 2 Resistors In Series have been planned, evaluated under subject Improvement Activities. Check our CBSE Class 10 Lab Manual for Chapter 2 Resistors In Series. We are grateful to the teachers for their constant support provided in the preparation of this CBSE Class 10 Lab Manual.

CBSE Class 10 Lab Manual for Chapter 2 Resistors In Series

The laboratory is important for making the study complete, especially for a subject like Science and Maths. CBSE has included the practicals in secondary class intending to make students familiarised with the basic tools and techniques used in the labs. With the help of this, they can successfully perform the experiments listed in the CBSE Class 10 Lab Manual.

CBSE Class 10 Lab Manual for Chapter 2 Resistors In Series Features:

• Basic Concept of Experiments
• Before performing the experiments the basic concept section of every experiment helps the students in know the aim of the experiment and to achieve the result with the minimum mistake
• Lab Experiments with Interactive session and NCERT Lab Manual Questions 
• Completely solved CBSE Class 10 Lab Manual Questions are provided.
• Practical Based Questions
• PBQs based on every experiment with their answers, covering Previous Years’ Questions, are provided experiments for complete coverage of concepts Web support

By performing the experiments, students will know the concept in a better way as they can now view the changes happening in front of their eyes. Their basics will become solid as they will learn by doing things. By doing this activity they will also get generated their interest in the subject. Students will develop questioning skills and start studying from a scientific perspective. Here we have given all the necessary details that a Chapter 2 Resistors In Series student should know about CBSE Class 10 Lab Manual. From CBSE Science practical to Lab manual, project work, important questions and CBSE lab kit manual, all the information is given in the elaborated form further in this page for Chapter 2 Resistors In Series students.

Benefit of the CBSE Class 10 Lab Manual for Chapter 2 Resistors In Series:

• Basic concepts of every experiment have been covered for better understanding. The matter is presented in the simple and lucid language under main-headings and sub-headings.
• Detailed observation tables and graphical design of experiments are provided wherever it is necessary.
• Diagrams are well-labelled and neatly drawn.
• CBSE Class 10 Lab Manual Questions with their answers
• Multiple Choice Questions (MCQs) are completely solved with the scoring key giving the explanation of every answer
• Group/Suggested Activities have also been given.
• Two Practice question Papers have also been included based on the latest guidelines issued by the CBSE.

The CBSE is a prestigious educational board in India that conducts the final examinations for the Chapter 2 Resistors In Series. The syllabus for the practical exam is designed by CBSE according to the CCE guidelines.

• NCERT Solutions for Class 12 Maths
• NCERT Solutions for Class 10 Maths
• CBSE Syllabus 2023-24
• Social Media Channels
• Login Customize Your Notification Preferences

One Last Step...

• Second click on the toggle icon

Provide prime members with unlimited access to all study materials in PDF format.

Allow prime members to attempt MCQ tests multiple times to enhance their learning and understanding.

Provide prime users with access to exclusive PDF study materials that are not available to regular users.

• Electric Circuit
• Resistor Series Parallel

Resistors in Series and Parallel

The combination of resistors – in series and parallel.

In an electric circuit, various components can be connected either in series or in parallel manner to produce different resistive networks. Sometimes, in the same circuit, resistors can be connected in parallel and series, across different loops to produce a more complex resistive network. Resistors are said to be in series if they are joined end to end such that the same current flows through all of them. The first end of the first resistance and the last end of the last resistor is connected to the cell terminals as shown. Since the current flowing through each resistor is the same, using Ohm’s Law:

\(\begin{array}{l}V_1 = I R_1 \textup{ and } V_2 = I R_2\end{array} \)

The equivalent resistance, R must obey

\(\begin{array}{l}V = I R\end{array} \)

Since the potential difference across the two resistors must be equal to the voltage drops across each resistance,

\(\begin{array}{l}V = V_1 ~+ ~V_2\end{array} \)

\(\begin{array}{l}I R = I R_1 ~+ ~I R_2\end{array} \)

\(\begin{array}{l}R = R_1~ +~ R_2\end{array} \)

Read More: Ohm’s Law

Series connection across the battery

Watch the video and learn more about infinite network of series

Resistors in Series

Resistors are said to be connected in series pattern, if the same amount of current flows through them. The corollary is also true, i.e., if they are connected in series, then the same amount of current flows through them.

Series connection of resistors

If the resistors in a circuit are all connected in series, like the figure given above, then the total resistance of the system is given by the following relation.

\(\begin{array}{l}R_{total} = R_1~ +~R_2~ +~ …..~ +~ R_n\end{array} \)

The total resistance of the system is just the sum total of individual resistances.

For example, consider the following sample problem.

A resistor having an electrical resistance value of 100 ohms, is connected to another resistor with a resistance value of 200 ohms. The two resistances are connected in series. What is the total resistance across the system?

Here, \(\begin{array}{l}R_1 = 100 ~Ω \textup{ and } R_2 = 200~ Ω\end{array} \)

\(\begin{array}{l}R_{total} = 100 ~+ ~200 = 300~ Ω\end{array} \)

Resistors in Parallel

A parallel combination of two resistors is shown below:

Parallel connection of resistors across voltage source

The main current I divides into two I 1 and 2 which flow into the resistors R 1 and R 2 respectively. Both the resistors’ ends are connected with each other and hence experience the same potential difference V.

Using Ohm’s Law, we know that

\(\begin{array}{l}I_1 = \frac{V}{R_1}\end{array} \) \(\begin{array}{l}I_2 = \frac{V}{R_2}\end{array} \)

Also, for the equivalent resistance, R:

\(\begin{array}{l}I = \frac{V}{R}\end{array} \)

Since, \(\begin{array}{l}I = I_1~+~ I_2\end{array} \)

\(\begin{array}{l}\frac{V}{R} = \frac{V}{R_1}~ +~\frac{V}{R_2}\end{array} \)

\(\begin{array}{l}\frac{1}{R} = \frac{1}{R_1} ~+~\frac{1}{R_2}\end{array} \)

In general, any number of resistances in parallel can be written as:

Parallel connection of resistors

\(\begin{array}{l}\frac{1}{R} = \frac{1}{R_1} ~+~\frac{1}{R_2}~ +~⋯~+~\frac{1}{R_n}\end{array} \)

For the problem given above, what if the resistors were connected in parallel instead of in series? What is the total resistance in that case?

\(\begin{array}{l}\frac{1}{R_{total}} = \frac{1}{100}~ + ~\frac{1}{200}\end{array} \)

\(\begin{array}{l}=\frac{(200~ +~ 100)}{20000}\end{array} \)

\(\begin{array}{l}=\frac{300}{20000}\end{array} \)

Therefore, \(\begin{array}{l}R_{total} = \frac{20000}{300} = 66.67 ~Ω\end{array} \)

Stay tuned with BYJU’S to learn more about resistors in series, resistors in parallel and much more.

Put your understanding of this concept to test by answering a few MCQs. Click ‘Start Quiz’ to begin!

Select the correct answer and click on the “Finish” button Check your score and answers at the end of the quiz

Visit BYJU’S for all Physics related queries and study materials

Your result is as below

Request OTP on Voice Call

Leave a Comment Cancel reply

Your Mobile number and Email id will not be published. Required fields are marked *

Post My Comment

Register with BYJU'S & Download Free PDFs

Register with byju's & watch live videos.

• Class 6 Maths
• Class 6 Science
• Class 6 Social Science
• Class 6 English
• Class 7 Maths
• Class 7 Science
• Class 7 Social Science
• Class 7 English
• Class 8 Maths
• Class 8 Science
• Class 8 Social Science
• Class 8 English
• Class 9 Maths
• Class 9 Science
• Class 9 Social Science
• Class 9 English
• Class 10 Maths
• Class 10 Science
• Class 10 Social Science
• Class 10 English
• Class 11 Maths
• Class 11 Computer Science (Python)
• Class 11 English
• Class 12 Maths
• Class 12 English
• Class 12 Economics
• Class 12 Accountancy
• Class 12 Physics
• Class 12 Chemistry
• Class 12 Biology
• Class 12 Computer Science (Python)
• Class 12 Physical Education
• GST and Accounting Course
• Excel Course
• Tally Course
• Finance and CMA Data Course
• Payroll Course

Interesting

• Learn English
• Learn Excel
• Learn Tally
• Learn GST (Goods and Services Tax)
• Learn Accounting and Finance
• GST Tax Invoice Format
• Accounts Tax Practical
• Tally Ledger List
• GSTR 2A - JSON to Excel

Are you in school ? Do you love Teachoo?

We would love to talk to you! Please fill this form so that we can contact you

• NCERT Questions
• Questions from Inside the chapter
• Examples from NCERT Book
• Teachoo Questions
• MCQs from (Past Year Papers & NCERT Exemplar)
• Assertion Reasoning questions (MCQ)
• Case Based Questions (MCQ)
• Past Year - 1 Mark Questions
• Past Year - 2 Mark Questions
• Past Year - 3 Mark Questions
• Past Year - 5 Mark Questions

Resistance in Series

Last updated at April 16, 2024 by Teachoo

In this type of combination, different resistors are joined end to end. (one after the another)

This is done to Increase Resistance of Circuit

In this case Total Resistance of circuit is equal to sum of Individual Resistance of the Resistors

R = R 1 + R 2 + R 3

Suppose Resistance of 2 resistors are 20 Ω and 30 Ω

Hence,R 1 = 20 Ω and R 2 = 30 Ω

Total Resistance = R 1 + R 2 = 20 + 30 = 50 Ω

IMPORTANT POINTS

When 2 resistors are connected in series.

• Same Current flows throughout the circuit in all resistors Let it be denoted by I
• Potential Difference across combination of Resistors is equal to total Potential Difference of Each Resistor Suppose 3 Different Resistors have Potential Difference of V 1 , V 2 and V 3 Total Potential Difference V = V 1 + V 2 +V 3 Hence,Total Potential Difference is equal to voltage of the battery
• Total Resistance is equal to Individual Resistance of each Resistor Hence R = R 1 + R 2 + R 3

How is the Resistance formula Derived - for series circuits?

Resistance of first resistor+second resistor+third resistor = Total Resistance

Hence we can say that sum of Individual Resistance of 3 resistors is equal to Total Resistance

So more than one resistors are combined together to increase resistance of the circuit

More the Resistance,less the current flows through circuit

Hence,this method is used to reduce current flow in circuit

Note - : In case of series, the total resistance is always greater than the resistance of the resistors. The resistance produced is highest when resistors are connected in series.

Note - : An ammeter is connected in series in a circuit so that it can detect the net current flowing in a circuit.

Q1 Page 213 - Draw a schematic diagram of a circuit consisting of a battery of three cells of 2V each , a 5Ω resistor, an 8 Ω resistor, and a 12 Ω resistor. And a plug key, all connected in series.

View Answer

Q2 Page 213 - Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 Ω resistor. What would be the readings in the ammeter and the voltmeter?

Example 12.7 - An electric lamp, whose resistance is 20 Ω, and a conductor of 4 Ωresistance are connected to a 6 V battery (Fig. 12.9). Calculate (a) the total resistance of the circuit, (b) the current through the circuit, and (c) the potential difference across the electric lamp and conductor.

Question 4 - What is the maximum resistance which can be made using five

(a) 1/5 Ω

(b) 10 Ω

(c) 5 Ω

(d) 1 Ω

Question 9 - A cell, a resistor, a key and ammeter are arranged as shown in the circuit diagrams below. The current recorded in the ammeter will be

(a) maximum in (i)

(b) maximum in (ii)

(c) maximum in (iii)

(d) the same in all the cases

Question 11 - Why does Ammeter have low resistance? Given reason

Why does Voltmeter have high resistance?

How is the Resistance formula Derived - for Series circuits? In series circuit, Current is same Let Current in circuit = I Now, Total Voltage = Voltage in R1 + Voltage in R2 + Voltage in R3 Voltage in R1 V1 = IR1 Voltage in R2 V2 = IR2 Voltage in R3 V3 = IR3 Also, Total Voltage = Total Current × Total Resistance Since current in Circuit = Total Current = I Total Voltage = I × Total Resistance Now, Total Voltage = V1 + V2 + V3 I × Total Resistance = IR1 + IR2 + IR3 I × Total Resistance = I × (R1 + R2 + R3) Total Resistance = R1 + R2 + R3 Thus, Total Resistance = R1 + R2 + R3

Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 14 years and a teacher from the past 18 years. He teaches Science, Economics, Accounting and English at Teachoo

Hi, it looks like you're using AdBlock :(

Please login to view more pages. it's free :), solve all your doubts with teachoo black.