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MATLAB: How do I fix subscripted assignment dimension mismatch?
new_img is ==>
curMean is like this: [double, double, double]
so what is wrong here?
- Assuming rows and cols are within loops and there are assigned a value and curMean is assigned a value then there should be nothing wrong, curMean is assigned to the z/j ( whichever you want to call it ) part of your multidimensional array. – phwd Commented Jan 25, 2011 at 17:31
- rows and cols are each lists of indexes. =\ – NullVoxPopuli Commented Jan 25, 2011 at 17:33
2 Answers 2
will only work if rows and cols are scalar values. If they are vectors, there are a few options you have to perform the assignment correctly depending on exactly what sort of assignment you are doing. As Jonas mentions in his answer , you can either assign values for every pairwise combination of indices in rows and cols , or you can assign values for each pair [rows(i),cols(i)] . For the case where you are assigning values for every pairwise combination, here are a couple of the ways you can do it:
Break up the assignment into 3 steps, one for each plane in the third dimension:
You could also do this in a for loop as Jonas suggested , but for such a small number of iterations I kinda like to use an "unrolled" version like above.
Use the functions RESHAPE and REPMAT on curMean to reshape and replicate the vector so that it matches the dimensions of the sub-indexed section of new_img :
For an example of how the above works, let's say I have the following:
Either of the above solutions will give you this result:
Be careful with such assignments!
In other words, you assign all combinations of row and column indices. If that's what you want, writing
should get what you want (as @gnovice suggested).
However, if rows and cols are matched pairs (i.e. you'd only want to assign 1 to elements (1,1) and (3,3) in the above example), you may be better off writing
- +1 Good point about matched pairs versus all pairwise combinations. – gnovice Commented Jan 25, 2011 at 18:04
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??? Subscripted assignment dimension mismatch
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Why do I get the "Subscripted assignment dimension mismatch" error message?
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Why do I get the "Subscripted assignment dimension mismatch" error message?
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Subscripted assignment dimension mismatch for table variable 'A'.
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I want to initialize a table with 4 empty rows and replace each row one by one. The first variable is string, and others are numerical. But an error pops up as: "Subscripted assignment dimension mismatch for table variable 'f1'".
This error occurs when you attempt to assign elements to an existing array, but the size of the variable you are trying to assign is not compatible with the existing array. For example, the following code snippet produces this error:
Use the functions RESHAPE and REPMAT on curMean to reshape and replicate the vector so that it matches the dimensions of the sub-indexed section of new_img: nRows = numel(rows); %# The number of indices in rows nCols = numel(cols); %# The number of indices in cols new_img(rows,cols,:) = repmat(reshape(curMean,[1 1 3]),[nRows nCols]);
Subscripted assignment dimension mismatch for table variable. I'm having troubles preallocating a table. My data looks something similar to this where one of the columns of the table is not just a scalar.
Learn more about subscripted assignment dimension mismatch., subscripted assignment dimension mismatch, subscripted assignment dimension mismatch for loop Here is the code that I'm getting the error: for z=1:length(X) V(z)=[X(z):Y]; end where X is a 1x81 matrix and Y is an integer
Subscripted assignment dimension mismatch. Follow. 2 views (last 30 days) Show older comments. harley on 5 Oct 2013. Vote. 0. Link. Commented: Cedric on 5 Oct 2013. Accepted Answer: Cedric. Open in MATLAB Online. how do I fix this assignment error? Theme. Copy. lambdaMJ = 7.2; MJ_Flow = (30/60)*2; A = 100; B = 1; C = 70; D = 4; E = C + D;
Subscripted assignment dimension mismatch. Error in ==> single_decode at 15. watermarked_image_row (1,c:z)=watermarked_image (a,1:y); Can anybody help me remove this error? I am using a test image of size 256*256 and lsb_image.bmp of 12*9.
This error occurs when you attempt to assign elements to an existing array, but the size of the variable you are trying to assign is not compatible with the existing array. For example, the following code snippet produces this error:
Why do I get the following error message sometimes: ERROR: ??? Subscripted assignment dimension mismatch. ??? In an assignment A(I) = B, the number of elements in B and I must be the same. ERROR:
Learn more about table for j=1:1:P A = raw(strcmp(data,reference),[2, 5, 6, 11:16]); B=table2cell(A); T(j,:)=table(B) end error: Subscripted assignment dimension mismatch for table variable 'A'.