If you haven't already read the page about , you should do so before you go on.

Use the BACK button on your browser to return to this page, or come back via the rates of reaction menu.

As you increase the temperature the rate of reaction increases. As a rough approximation, for many reactions happening at around room temperature, the rate of reaction doubles for every 10°C rise in temperature.

You have to be careful not to take this too literally. It doesn't apply to all reactions. Even where it is approximately true, it may be that the rate doubles every 9°C or 11°C or whatever. The number of degrees needed to double the rate will also change gradually as the temperature increases.

You will find the explored in a slightly more mathematical way on a separate page.

Some reactions are virtually instantaneous - for example, a precipitation reaction involving the coming together of ions in solution to make an insoluble solid, or the reaction between hydrogen ions from an acid and hydroxide ions from an alkali in solution. So heating one of these won't make any noticeable difference to the rate of the reaction.

Almost any other reaction you care to name will happen faster if you heat it - either in the lab, or in industry.

Particles can only react when they collide. If you heat a substance, the particles move faster and so collide more frequently. That will speed up the rate of reaction.

That seems a fairly straightforward explanation until you look at the numbers!

It turns out that the frequency of two-particle collisions in gases is proportional to the square root of the kelvin temperature. If you increase the temperature from 293 K to 303 K (20°C to 30°C), you will increase the collision frequency by a factor of:

That's an increase of 1.7% for a 10° rise. The rate of reaction will probably have doubled for that increase in temperature - in other words, an increase of about 100%. The effect of increasing collision frequency on the rate of the reaction is minor. The important effect is quite different . . .

Collisions only result in a reaction if the particles collide with enough energy to get the reaction started. This minimum energy required is called the activation energy for the reaction.

What follows assumes you have a reasonable idea about activation energy and its relationship with the Maxwell-Boltzmann distribution. This is covered on the introductory page about .

If you aren't confident about this, follow this link, and use the BACK button on your browser to return to this page.

Only those particles represented by the area to the right of the activation energy will have enough energy to react when they collide. The great majority don't have enough energy, and will simply bounce apart. If there are very few particles with enough energy at any time, then the reaction will be slow.

I have already commented on this on the introductory page about . It is important to realise that although the shape of this graph is constant at a given temperature, which part of it an individual particle finds itself in is constantly changing. Some particles will gain energy in random collisions, and others will lose energy.

Just by chance, every particle will at some time find itself with enough energy to react if it makes a successful collision. So although at any instant there may only be relatively few particles present with enough energy, given time all the particles will react if the reacting proportions are right.

In the next diagram, the graph labelled is at the original temperature. The graph labelled is at a higher temperature.

If you now mark the position of the activation energy, you can see that although the curve hasn't moved very much overall, there has been such a large increase in the number of the very energetic particles that many more now collide with enough energy to react.

Remember that the area under a curve gives a count of the number of particles. On the last diagram, the area under the higher temperature curve to the right of the activation energy looks to have at least doubled - therefore at least doubling the rate of the reaction.

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing the activation energy for the reaction) which result in a reaction.

You will find questions about all the factors affecting rates of reaction on the page about catalysts at the end of this sequence of pages.

Where would you like to go now?

To the rates of reaction menu . . .

To the Physical Chemistry menu . . .

To Main Menu . . .

© Jim Clark 2002 (last modified October 2018)

Core Chemistry 14 - 16

As a rough and ready guide, increasing the temperature by 10°C doubles the rate of a reaction.

You mustn't take this too literally. It doesn't apply to all reactions. Even where it is approximately true, it may be that the rate doubles every 9°C or 11°C or whatever. The number of degrees needed to double the rate will also change gradually as the temperature increases.

Heating something up makes the particles move faster. If they move faster, they will collide more often - and so the possibility of a reaction happening increases.

The trouble with this explanation is that it only makes up a very tiny proportion of the observed change in reaction rate as you increase the temperature.

For a typical reaction around room temperature, if you increase the temperature by 10°C, the collision rate only increases by a bit less than 2%. But the reaction rate will approximately double - an increase of about 100%.

To understand the next bit, you have to be confident about energy diagrams in chemical reactions and the terms exothermic and endothermic. You may need to refer to the page .

On that page, you will have found this simple energy diagram for the reaction between hydrogen and oxygen.

This is a very exothermic reaction, giving out a lot of heat when the gases combine to make water. The system becomes more energetically stable after the hydrogen and oxygen combine together.

So why don't hydrogen and oxygen react immediately on mixing if they become more stable by reacting?

For any reaction to happen, bonds need to be broken, and new bonds formed. Breaking bonds costs energy; energy is released when new bonds form.

In the reaction between hydrogen and oxygen, you have to put quite a lot of energy in to break the bonds in the hydrogen and oxygen molecules.

In a hydrogen / oxygen mixture at ordinary temperatures, collisions between the molecules don't generate enough energy to achieve this.

The minimum amount of energy needed for a collision to produce a reaction is called the .

We can modify the last diagram to show this. This is called a . The diagram below serves for any exothermic reaction.

You can draw a similar diagram for an endothermic reaction.

This time, of course, the activation energy is much greater.

The temperature of a substance is related to the average kinetic energy of its particles. If the average kinetic energy goes up, you will see that as an increase in temperature.

But this is an kinetic energy. Within that, individual particles may have quite a low energy, or a moderate energy or a very high energy - and that will be changing all the time as particles collide with each other.

However, the average will still stay the same at a particular temperature.

What we are really interested in from the point of view of reaction rates are the particles which have high enough energies at the time so that when they collide, they reach activation energy.

The particles with moderate or low energies will just bump off each other again without any reaction happening.

Kinetic energy is related to both the mass of a particle and its speed by the formula

KE = ½mv

So a higher speed for a given particle is associated with a higher kinetic energy.

For a reaction to happen, collisions must generate an energy equal to or greater than activation energy. So we are only interested in those particles which have very high kinetic energies at that time.

Increasing the temperature doesn't have the same proportional effect on all the particles. Instead, it produces a big increase in the number of the most active particles.

So the main influence of temperature on reaction rates is to produce a large increase in the number of particles whose collisions will have energies equal to or greater than activation energy.

A commonly used experiment to show the effect of temperature on rate is the reaction between dilute hydrochloric acid and sodium thiosulfate solution which you will already have seen on the page about the effect of concentration on reaction rates.

Na S O (aq) + 2HCl(aq)  (g) + S(s) + H O(l)

If you haven't read that recently (or at all) it is important that you read the before you go any further. I have covered all the necessary background that you will need for the rest of this page on that page, and I'm not repeating it.

The video shows this happening by mixing increasing amounts of cold sodium thiosulfate solution with a warm solution of the same concentration.

There is a problem in the way these experiments were done. The temperature was measured each time the acid was added. Adding cold acid will decrease the temperature of the reaction mixture - and that is what we should be measuring. You should take the temperature you add the acid, not before.

Clearly, the higher the temperature, the shorter time it takes for the cross to disappear, and so the faster the reaction.

Does this bear out the approximation that a 10°C temperature rise roughly doubles the rate of reaction? You can find that out by looking at the graph on the video.

At 20°C, it takes about 250 seconds; at 30°C, it takes about 125 seconds. It has halved the time for the cross to disappear, and so doubled the rate.

At 40°C, the time taken is between 60 and 70 seconds - approximately halved again and so another doubling of the rate.

This isn't a very well-drawn smooth graph, so there is no point in measuring it exactly. All I am trying to show is that the shape is consistent with an approximate doubling of rate for every 10°C temperature increase.

  • Chemistry Practicals
  • CBSE Class 12 Chemistry Practical
  • Effect Of Temperature On The Rate Of Reaction Between Sodium Thiosulphate And Hydrochloric Acid

Effect of temperature on the rate of reaction between sodium thiosulphate and hydrochloric acid

In this article, we have discussed the effect of temperature on the rate of reaction between hydrochloric acid and sodium thiosulphate.

The aim of this experiment – Understanding the effect of temperature variation on the rate of reaction between hydrochloric acid and sodium thiosulphate.

The rate of a chemical reaction is directly proportional to the temperature. As the temperature increases, the reaction rate also increases. With the increase in temperature the kinetic energy of the molecules also increases. Usually, it is observed that for every 10-degree increase in temperature the rate of reaction is doubled. Therefore, the rate of reaction of hydrochloric acid and sodium thiosulphate also increases with rise in temperature.

 

Materials required:

The apparatus and materials required for this experiment are as follows:

  • Conical flask of volume 250 mL
  • Tripod stand
  • Measuring cylinder
  • Thermometer
  • 0.1M sodium thiosulphate solution
  • Concentrated nitric acid
  • Distilled water
  • 1M hydrochloric acid

The effect of temperature on the rate of reaction:

  • Take a conical flask of volume 100 mL.
  • Add 50 mL of 0.1M sodium thiosulphate solution to it.
  • With the help of a thermometer measure, the temperature of the solution which is added to the flask.
  • Take 1M HCl of volume 10 mL with the help of a burette and add it to the conical flask containing sodium thiosulphate.
  • Start the stopwatch as soon as you have poured half of the hydrochloric acid into the flask containing sodium thiosulphate solution.
  • Take a white tile and draw a cross mark on it.
  • Shake the conical flask and place it on the tile.
  • Observe the flask and start the stop-watch as soon as the cross mark becomes invisible.
  • Empty the flask and wash it with concentrated nitric acid first and later with distilled water.
  • Take the washed flask add 50 mL of 0.1M sodium thiosulphate solution and heat it to (T+ 10)°.
  • Continue the steps from points 4.
  • Repeat the experiment for (T+ 20) °C, (T+ 30) °C, (T+ 40) °C and record the results.
  • Record the time taken for the process.

Observation and result

Trials

 

Temperature (T)

 

Time (t)

 

1/t

 

1 T
2 (T+ 10) °C
3 (T+ 120) °C
4 (T+ 30) °C
5 (T+ 40) °C

Precautions to be taken during the experiment:

  • Thoroughly wash the apparatus with concentrated nitric acid and distilled water.
  • Take the exact quantity of solutions needed for this experiment.
  • Complete the experiment in one go to avoid temperature variations.
  • Use THE same tile for all the observations.
  • Stay alert while you start and stop the stop-watch.

1. What is the concentration of sodium thiosulphate used for this experiment?

2. What is the concentration of hydrochloric acid used for this experiment?

3. When to start the stop-watch?

Ans: As soon as you pour half of HCl into the flask containing sodium thiosulphate solution.

4. Name the two solutions used in this experiment.

Ans: Hydrochloric acid and sodium thiosulphate.

5. What is the importance of concentrated nitric acid?

Ans: It is used in thorough washing of the apparatus used in the experiment. After washing the apparatus with HNO 3 rinse it with distilled water.

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Question Video: Interpreting Graphs on the Effect of Temperature on the Rate of Enzyme-Controlled Reactions to Determine Optimum Temperature Biology • First Year of Secondary School

The graph shows the rate of an enzyme-controlled reaction relative to temperature. How would you be able to determine an enzyme’s optimum temperature from a graph?

Video Transcript

The graph provided shows the rate of an enzyme-controlled reaction relative to temperature. How would you be able to determine an enzyme’s optimum temperature from a graph? (A) It is the temperature at which the reaction is completed. (B) It is always the first temperature recorded on the graph. (C) It is the temperature at which the rate of reaction is fastest. Or (D) it is the final temperature minus the temperature at which the rate of reaction is slowest.

Enzymes are biological catalysts. They speed up chemical reactions but remain unchanged during this process. Enzymes are globular proteins. Each type of enzyme has a specific structure and shape. This includes a region called an active site, which is where the substrate molecule will bind in order for the reaction to take place.

Since enzymes are proteins, they can be denatured by changing conditions, such as pH and temperature. This means that the bonds holding the protein structure in place are disrupted, which changes the shape of the active site. If the active site changes shape, the substrate can no longer fit. Therefore, the reaction can no longer be catalyzed by the enzyme.

Different enzymes have different optimum conditions. An enzyme will work best at a specific temperature and pH. As the graph shows, as the temperature increases, the rate of reaction also increases. An increase in temperature increases the kinetic energy of both the enzyme and substrate molecules. They move around more quickly, increasing the frequency of successful collisions, thus increasing the rate of reaction.

The optimum temperature is the temperature at which an enzyme-controlled reaction occurs at its highest rate. If we look at our graph, we can see that the rate of reaction increases as the temperature increases up to 50 degrees Celsius. Above this temperature, the rate of reaction starts to decrease as the enzymes become denatured.

We now have enough information to answer our question. The correct way to determine an enzyme’s optimum temperature from a graph is given in answer choice (C). It is the temperature at which the rate of reaction is fastest.

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The effect of concentration on reaction rate

  • Four out of five

Start your stopwatches, and get ready to learn about reaction rates. Mixing different solutions of sodium thiosulfate with an acid will result in sulfur precipitate forming at different speeds. Will students keep track?

Create a lesson of discovery where students put their knowledge of concentrations and reactions into practical use. This experiment uses simple chemicals and equipment found in your learning space. 

This experiment should take 60 minutes.

  • Eye protection
  • Conical flask, 250 cm 3
  • Measuring cylinder, 100 cm 3
  • Sodium thiosulfate solution 50 g dm –3
  • Hydrochloric acid 2 mol dm –3

Health, safety and technical notes

  • Read our standard health and safety guidance . 
  • Always wear eye protection.
  • Sodium thiosulfate solution 50 g dm –3 is low hazard (see CLEAPPS Hazcard HC095a ).
  • Dilute hydrochloric acid is low hazard at the concentration used (see CLEAPSS Hazcard HC057a ).
  • Put 50 cm 3 of sodium thiosulfate solution in a flask.
  • Measure 5 cm 3 of dilute hydrochloric acid in a small measuring cylinder.
  • Add the acid to the flask and immediately start the clock. Swirl the flask to mix the solutions and place it on a piece of paper marked with a cross.
  • Look down at the cross from above. When the cross disappears, stop the clock and note the time. Record this in the table provided on the student sheet.
  • Repeat this using different concentrations of sodium thiosulfate solution. Make up 50 cm 3 of each solution. Mix different volumes of the sodium thiosulfate solution with water as shown in the table.
  • As soon as possible, pour the solution down the sink (in the fume cupboard if possible) and wash away.
  • Calculate the concentration of sodium thiosulfate in the flask at the start of each experiment. Record the results in the table provided on the student sheet.
  • For each set of results, calculate the value of 1/time. (This value can be taken as a measure of the rate of reaction).
  • Plot a graph of 1/time taken on the vertical (y) axis and concentration on the horizontal (x) axis.
  • Sulfur dioxide (a toxic gas) forms as a by-product. Ensure good ventilation. If there are asthmatics in the class, the risk assessment should take this into account and necessary adjustments made, such as working in a fume cupboard, reducing the scale etc.
  • As soon as the reaction is complete, pour the solutions away, preferably into the fume cupboard sink. Wash away with plenty of water.
  • A light sensor can be used to monitor the precipitation on a computer. The result, in the form of graphs on the computer, can be analysed using data logging software.
  • A light sensor clamped against a plastic cuvette filled with the reactants substitutes for a colorimeter. The data logging software shows the turbidity on a graph, and this tends to yield more detail than the standard end-point approach. The rate of change can be measured using the slope of the graph or the time taken for a change to occur.

More resources

Add context and inspire your learners with our short career videos showing how chemistry is making a difference .

The effect of concentration on reaction rate – student sheet

The effect of concentration on reaction rate – teacher notes, additional information.

This practical is part of our  Chemistry for Non-Specialists collection . This experiment has been adapted from Classic Chemistry Demonstrations, Royal Society of Chemistry, London, p.162-164

  • 14-16 years
  • 16-18 years
  • Practical experiments
  • Reactions and synthesis
  • Rates of reaction

Specification

  • AT.5 Making and recording of appropriate observations during chemical reactions including changes in temperature and the measurement of rates of reaction by a variety of methods such as production of gas and colour change.
  • 5 Investigate how changes in concentration affect the rates of reactions by a method involving measuring the volume of a gas produced and a method involving a change in colour or turbidity. This should be an investigation involving developing a hypothesi…
  • Factors which affect the rates of chemical reactions include: the concentrations of reactants in solution, the pressure of reacting gases, the surface area of solid reactants, the temperature and the presence of catalysts.
  • Students should be able to recall how changing these factors affects the rate of chemical reactions.
  • RP19 Investigation of how changes in concentration affect the rates of reactions by a method involving measuring the volume of a gas produced and a method involving a change in colour or turbidity. This should be an investigation involving developing…
  • Explain the effects on rates of reaction of changes in temperature, concentration and pressure in terms of the frequency and energy of collision between particles.
  • Describe the effect of changes in temperature, concentration, pressure, and surface area on rate of reaction.
  • 11 Investigate how changes in concentration affect the rates of reactions by a method involving measuring the volume of a gas produced and a method involving a change in colour or turbidity. This should be an investigation involving developing…
  • 5 Making and recording of appropriate observations during chemical reactions including changes in temperature and the measurement of rates of reaction by a variety of methods such as production of gas and colour change
  • 7.1b observing a colour change (in the reaction between sodium thiosulfate and hydrochloric acid)
  • 7.4 Explain the effects on rates of reaction of changes in temperature, concentration, surface area to volume ratio of a solid and pressure (on reactions involving gases) in terms of frequency and/or energy of collisions between particles
  • 8 Investigation the effect of surface area, concentration and temperature on the rate of a chemical reaction
  • Making and recording of appropriate observations during chemical reactions including changes in temperature and the measurement of rates of reaction by a variety of methods such as production of gas and colour change
  • C6.2.1 describe the effect on rate of reaction of changes in temperature, concentration, pressure, and surface area
  • C6.2.2 explain the effects on rates of reaction of changes in temperature, concentration and pressure in terms of frequency and energy of collision between particles
  • C5 Investigation the effect of surface area, concentration and temperature on the rate of a chemical reaction
  • C5.1c describe the effect of changes in temperature, concentration, pressure, and surface area on rate of reaction
  • C5.1d explain the effects on rates of reaction of changes in temperature, concentration and pressure in terms of frequency and energy of collision between particles
  • C5.2c describe the effect of changes in temperature, concentration, pressure, and surface area on rate of reaction
  • C5.2d explain the effects on rates of reaction of changes in temperature, concentration and pressure in terms of frequency and energy of collision between particles
  • concentration
  • by increasing the concentration of a reactant
  • (b) the effect of changes in temperature, concentration (pressure) and surface area on rate of reaction
  • Use of: graduated glassware (volume) such as measuring cylinders of varying sizes;
  • Use of: stopclock or stopwatch (time);
  • 2.3.1 demonstrate knowledge and understanding that the rate of a reaction may be determined by measuring the loss of a reactant or gain of a product over time and use the equation: rate = 1 / time
  • 2.3.2 suggest appropriate practical methods to measure the rate of a reaction and collect reliable data (methods limited to measuring a change in mass, gas volume or formation of a precipitate against time) for the reaction of: metals with dilute acid;…
  • 2.3.3 interpret experimental data quantitatively, for example drawing and interpreting appropriate graphs to determine the rate of reaction; and
  • 2.3.2 suggest appropriate practical methods to measure the rate of a reaction and collect reliable data (methods limited to measuring a change in mass, gas volume or formation of a precipitate against time) for the reaction of: metals with dilute acid…
  • Rate of reaction.
  • Concentration. Particle size.
  • Mandatory experiment 6.2 - Studying the effects on the reaction rate of (i) concentration and (ii) temperature, using sodium thiosulfate solution and hydrochloric acid

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  1. The effect of temperature on reaction rate

    The object is to repeat the experiment five times with temperatures in the range 15-55 °C. Put the conical flask over a piece of paper with a cross drawn on it. Add the acid and start the clock. Swirl the flask to mix the solutions and place it on a piece of white paper marked with a cross. Take the initial temperature of the mixture.

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  5. PDF Examining the Effect of Temperature on Reaction Rate

    Refer to the experiment entitled "Determining the Rate Law for a Chemical Reaction". The Arrhenius equation is. -E. = A e. RT. (eq. 3) where k is the rate constant, A is called the frequency factor, Ea is the activation energy (in J/mole), R is the gas constant 8.314 J/K-mole, and T is the Kelvin temperature.

  6. PDF The Effect of Temperature and Concentration on Reaction Rate

    In this experiment, the effect of temperature and concentration on the rate of a chemical reaction will be studied. The reaction chosen, frequently termed the "clock reaction", is actually a series of consecutive reactions represented by the following equations: BrO3 1- + 6 I1- + 6H+ Br1- + 3I2 + 3 H2O. (1)

  7. PDF The Effect of Temperature and Concentration on Reaction Rate

    In this experiment, the effect of temperature and concentration on the rate of a chemical reaction will be studied. The reaction chosen, frequently termed the "clock reaction", is actually a series of consecutive reactions represented by the following equations: HIO3 + 3 Na2SO3 → HI + 3 Na2SO4. 3 H2O + 3 l2.

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  13. Interpreting Graphs on the Effect of Temperature on the Rate of Enzyme

    How would you be able to determine an enzyme's optimum temperature from a graph? (A) It is the temperature at which the reaction is completed. (B) It is always the first temperature recorded on the graph. (C) It is the temperature at which the rate of reaction is fastest. Or (D) it is the final temperature minus the temperature at which the ...

  14. The rate of reaction of magnesium with hydrochloric acid

    (HT) Calculate the gradient of a tangent to the curve on these graphs as a measure of rate of reaction at a specific time. AQA Combined science: Synergy. 4.7 Movement and interactions. 4.7.4 The rate and extent of chemical change. 4.7.4.1 Factors that affect reaction rates. Suggest practical methods for determining the rate of a given reaction.

  15. The effect of concentration on reaction rate

    Calculate the concentration of sodium thiosulfate in the flask at the start of each experiment. Record the results in the table provided on the student sheet. For each set of results, calculate the value of 1/time. (This value can be taken as a measure of the rate of reaction). Plot a graph of 1/time taken on the vertical (y) axis and ...